1, 2, 3, 4,5,6,7,8,9,OMG. You are absolutely hilarious. Trying to explain something simple, yet you still mess it up.
You said Votto had 5 of 40 plate appearances. That is 1/8. Please explain to everyone how a single player can can have plate appearances more than one out of nine!! Either the Reds cheated or math is not a strong suit for you.
(Hint: you forgot that walks, sacrifices and HBP are plate appearances but not ABs - The Reds had 44 or 45 plate appearances last night).
1,2, 3, 4,5,6,7,8,9
1,2, 3, 4,5,6,7,8,9
1,2, 3, 4,5,6,7,8,9
1,2, 3, 4
Batters 1, 2, 3 and 4 come to the plate 5 times out of 40 while batters 5, 6, 7,8,9 only come to the plate 4 times of 40.
Batters 1-4 therefore represent 12.5% (1/8 or 5/40) of the appearances and batters 5-9 each represent 10% (1/10 or 4/40) of appearances.
Not saying that is what actually occured in that specific game, but unless I'm missing something, that is very much what could occur, no cheating required.
A player having 14.29 % or 1/7 (4/28) of a teams plate appearances would be possible, though very rare, and most certainly would occur in a loss, not a win.
The very highest percentage I can think of as a percentage of a teams plate appearances would be 15.79% (3/19). That could only occur where the game was called after the sixth. I feel like I'm channeling my inner Lance Mccallister.
Guess math is not everyone's strong suit.
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